#!/bin/bash

# Print ANSI color codes

count=0
for i in {0..255}; do
  # Print the color-coded number, padded to 3 digits
  printf "\033[38;5;${i}m%3d\033[0m " $i

  # After printing 16 numbers, start a new line
  ((count++))
  if ((count == 16)); then
    echo
    count=0
  fi
done